Solve 3=sqrt{6-5t}+2

$$3 = \sqrt { 6 - 5 t } + 2$$

Solve for t

$$t=1$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{6-5t}+2=3$$

Subtract 2 from both sides.

$$\sqrt{6-5t}=3-2$$

Subtract 2 from 3 to get 1.

$$\sqrt{6-5t}=1$$

Square both sides of the equation.

$$-5t+6=1$$

Subtract 6 from both sides of the equation.

$$-5t+6-6=1-6$$

Subtracting 6 from itself leaves 0.

$$-5t=1-6$$

Subtract 6 from 1.

$$-5t=-5$$

Divide both sides by -5.

$$\frac{-5t}{-5}=-\frac{5}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$t=-\frac{5}{-5}$$

Divide -5 by -5.

$$t=1$$