Solve for x
x = \frac{19}{5} = 3\frac{4}{5} = 3.8
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\frac{5}{3}x-\frac{10}{3}=3
Swap sides so that all variable terms are on the left hand side.
\frac{5}{3}x=3+\frac{10}{3}
Add \frac{10}{3} to both sides.
\frac{5}{3}x=\frac{9}{3}+\frac{10}{3}
Convert 3 to fraction \frac{9}{3}.
\frac{5}{3}x=\frac{9+10}{3}
Since \frac{9}{3} and \frac{10}{3} have the same denominator, add them by adding their numerators.
\frac{5}{3}x=\frac{19}{3}
Add 9 and 10 to get 19.
x=\frac{19}{3}\times \frac{3}{5}
Multiply both sides by \frac{3}{5}, the reciprocal of \frac{5}{3}.
x=\frac{19\times 3}{3\times 5}
Multiply \frac{19}{3} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{19}{5}
Cancel out 3 in both numerator and denominator.
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Limits
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