Solve 3:1/10-(1-2/3)^-2+sqrt[3]{7/8-1}=

$$3 : \frac { 1 } { 10 } - ( 1 - \frac { 2 } { 3 } ) ^ { - 2 } + \sqrt[ 3 ] { \frac { 7 } { 8 } - 1 } =$$

Evaluate

$$\frac{41}{2}=20.5$$

Solution Steps

Divide 3 by \frac{1}{10} by multiplying 3 by the reciprocal of \frac{1}{10}.

$$3\times 10-\left(1-\frac{2}{3}\right)^{-2}+\sqrt[3]{\frac{7}{8}-1}$$

Multiply 3 and 10 to get 30.

$$30-\left(1-\frac{2}{3}\right)^{-2}+\sqrt[3]{\frac{7}{8}-1}$$

Subtract \frac{2}{3} from 1 to get \frac{1}{3}.

$$30-\left(\frac{1}{3}\right)^{-2}+\sqrt[3]{\frac{7}{8}-1}$$

Calculate \frac{1}{3} to the power of -2 and get 9.

$$30-9+\sqrt[3]{\frac{7}{8}-1}$$

Subtract 9 from 30 to get 21.

$$21+\sqrt[3]{\frac{7}{8}-1}$$

Subtract 1 from \frac{7}{8} to get -\frac{1}{8}.

$$21+\sqrt[3]{-\frac{1}{8}}$$

Calculate \sqrt[3]{-\frac{1}{8}} and get -\frac{1}{2}.

$$21-\frac{1}{2}$$

Subtract \frac{1}{2} from 21 to get \frac{41}{2}.

$$\frac{41}{2}$$

Factor

$$\frac{41}{2} = 20\frac{1}{2} = 20.5$$