Solve 3+8*1/2+sqrt[3]{8}+(1/2)^2-6/3

$$3 + 8 \cdot \frac { 1 } { 2 } + \sqrt[ 3 ] { 8 } + ( \frac { 1 } { 2 } ) ^ { 2 } - \frac { 6 } { 3 }$$

Evaluate

$$\frac{29}{4}=7.25$$

Solution Steps

Multiply 8 and \frac{1}{2} to get 4.

$$3+4+\sqrt[3]{8}+\left(\frac{1}{2}\right)^{2}-\frac{6}{3}$$

Add 3 and 4 to get 7.

$$7+\sqrt[3]{8}+\left(\frac{1}{2}\right)^{2}-\frac{6}{3}$$

Calculate \sqrt[3]{8} and get 2.

$$7+2+\left(\frac{1}{2}\right)^{2}-\frac{6}{3}$$

Add 7 and 2 to get 9.

$$9+\left(\frac{1}{2}\right)^{2}-\frac{6}{3}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$9+\frac{1}{4}-\frac{6}{3}$$

Add 9 and \frac{1}{4} to get \frac{37}{4}.

$$\frac{37}{4}-\frac{6}{3}$$

Divide 6 by 3 to get 2.

$$\frac{37}{4}-2$$

Subtract 2 from \frac{37}{4} to get \frac{29}{4}.

$$\frac{29}{4}$$

Factor

$$\frac{29}{2 ^ {2}} = 7\frac{1}{4} = 7.25$$