Solve 3+2k(M-2)=D

$$3 + 2 k ( M - 2 ) = D$$

Solve for D

$$D=2k\left(M-2\right)+3$$

Solution Steps

Use the distributive property to multiply 2k by M-2.

$$3+2kM-4k=D$$

Swap sides so that all variable terms are on the left hand side.

$$D=3+2kM-4k$$

Solve for M

$$\left\{\begin{matrix}M=-\frac{3-4k-D}{2k}\text{, }&k\neq 0\\M\in \mathrm{R}\text{, }&D=3\text{ and }k=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2k by M-2.

$$3+2kM-4k=D$$

Subtract 3 from both sides.

$$2kM-4k=D-3$$

Add 4k to both sides.

$$2kM=D-3+4k$$

The equation is in standard form.

$$2kM=D+4k-3$$

Divide both sides by 2k.

$$\frac{2kM}{2k}=\frac{D+4k-3}{2k}$$

Dividing by 2k undoes the multiplication by 2k.

$$M=\frac{D+4k-3}{2k}$$