Solve 3+2/4+5=19

$$3 + \frac { 2 } { 4 } + 5 = 19$$

Verify

Solution Steps

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$3+\frac{1}{2}+5=19$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{6}{2}+\frac{1}{2}+5=19$$

Since \frac{6}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{6+1}{2}+5=19$$

Add 6 and 1 to get 7.

$$\frac{7}{2}+5=19$$

Convert 5 to fraction \frac{10}{2}.

$$\frac{7}{2}+\frac{10}{2}=19$$

Since \frac{7}{2} and \frac{10}{2} have the same denominator, add them by adding their numerators.

$$\frac{7+10}{2}=19$$

Add 7 and 10 to get 17.

$$\frac{17}{2}=19$$

Convert 19 to fraction \frac{38}{2}.

$$\frac{17}{2}=\frac{38}{2}$$

Compare \frac{17}{2} and \frac{38}{2}.

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