Solve 3+[8-7/2*8-7-2]*2

$$3 + [ \frac { 8 - 7 } { 2 \times 8 - 7 - 2 } ] \times 2$$

Evaluate

$$\frac{23}{7}\approx 3.285714286$$

Solution Steps

Subtract 7 from 8 to get 1.

$$3+\frac{1}{2\times 8-7-2}\times 2$$

Multiply 2 and 8 to get 16.

$$3+\frac{1}{16-7-2}\times 2$$

Subtract 7 from 16 to get 9.

$$3+\frac{1}{9-2}\times 2$$

Subtract 2 from 9 to get 7.

$$3+\frac{1}{7}\times 2$$

Multiply \frac{1}{7} and 2 to get \frac{2}{7}.

$$3+\frac{2}{7}$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{21}{7}+\frac{2}{7}$$

Since \frac{21}{7} and \frac{2}{7} have the same denominator, add them by adding their numerators.

$$\frac{21+2}{7}$$

Add 21 and 2 to get 23.

$$\frac{23}{7}$$

Factor

$$\frac{23}{7} = 3\frac{2}{7} = 3.2857142857142856$$