Solve 3!-1/3+15!

$$3 ! - \frac { 1 } { 3 } + 15 !$$

Evaluate

$$\frac{3923023104017}{3}\approx 1.307674368 \cdot 10^{12}$$

Solution Steps

The factorial of 3 is 6.

$$6-\frac{1}{3}+15!$$

Convert 6 to fraction \frac{18}{3}.

$$\frac{18}{3}-\frac{1}{3}+15!$$

Since \frac{18}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{18-1}{3}+15!$$

Subtract 1 from 18 to get 17.

$$\frac{17}{3}+15!$$

The factorial of 15 is 1307674368000.

$$\frac{17}{3}[phone]$$

Convert 1307674368000 to fraction \frac{3923023104000}{3}.

$$\frac{17}{3}+\frac{3923023104000}{3}$$

Since \frac{17}{3} and \frac{3923023104000}{3} have the same denominator, add them by adding their numerators.

$$\frac{17+3923023104000}{3}$$

Add 17 and 3923023104000 to get 3923023104017.

$$\frac{3923023104017}{3}$$

Factor

$$\frac{919 \cdot 9491 \cdot 449773}{3} = 1307674368005\frac{2}{3} = 1307674368005.6667$$