Solve for x
x=\frac{2y-7}{3}
Solve for y
y=\frac{3x+7}{2}
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-3x=7-2y
Subtract 2y from both sides.
\frac{-3x}{-3}=\frac{7-2y}{-3}
Divide both sides by -3.
x=\frac{7-2y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{2y-7}{3}
Divide 7-2y by -3.
2y=7+3x
Add 3x to both sides.
2y=3x+7
The equation is in standard form.
\frac{2y}{2}=\frac{3x+7}{2}
Divide both sides by 2.
y=\frac{3x+7}{2}
Dividing by 2 undoes the multiplication by 2.
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