Solve 2y-x^2+1=0

$$2y- { x }^{ 2 } +1 = 0$$

Solve for y

$$y=\frac{x^{2}-1}{2}$$

Steps for Solving Linear Equation

Add x^{2} to both sides. Anything plus zero gives itself.

$$2y+1=x^{2}$$

Subtract 1 from both sides.

$$2y=x^{2}-1$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{x^{2}-1}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{x^{2}-1}{2}$$

Solve for x (complex solution)

$$x=-\sqrt{2y+1}$$

$$x=\sqrt{2y+1}$$

Solve for x

$$x=\sqrt{2y+1}$$

$$x=-\sqrt{2y+1}\text{, }y\geq -\frac{1}{2}$$