Solve for x
x=\frac{2\left(y+48\right)}{3}
Solve for y
y=\frac{3\left(x-32\right)}{2}
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3x=2y+96
Swap sides so that all variable terms are on the left hand side.
\frac{3x}{3}=\frac{2y+96}{3}
Divide both sides by 3.
x=\frac{2y+96}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{2y}{3}+32
Divide 96+2y by 3.
2y=3x-96
Subtract 96 from both sides.
\frac{2y}{2}=\frac{3x-96}{2}
Divide both sides by 2.
y=\frac{3x-96}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3x}{2}-48
Divide -96+3x by 2.
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