Solve 2xy-3x-4y+9=0

$$2xy-3x-4y+9=0$$

Solve for x

$$x=-\frac{9-4y}{2y-3}$$

$$y\neq \frac{3}{2}$$

Steps for Solving Linear Equation

Add 4y to both sides. Anything plus zero gives itself.

$$2xy-3x+9=4y$$

Subtract 9 from both sides.

$$2xy-3x=4y-9$$

Combine all terms containing x.

$$\left(2y-3\right)x=4y-9$$

Divide both sides by 2y-3.

$$\frac{\left(2y-3\right)x}{2y-3}=\frac{4y-9}{2y-3}$$

Dividing by 2y-3 undoes the multiplication by 2y-3.

$$x=\frac{4y-9}{2y-3}$$

Solve for y

$$y=-\frac{3\left(3-x\right)}{2\left(x-2\right)}$$

$$x\neq 2$$

Steps for Solving Linear Equation

Add 3x to both sides. Anything plus zero gives itself.

$$2xy-4y+9=3x$$

Subtract 9 from both sides.

$$2xy-4y=3x-9$$

Combine all terms containing y.

$$\left(2x-4\right)y=3x-9$$

Divide both sides by 2x-4.

$$\frac{\left(2x-4\right)y}{2x-4}=\frac{3x-9}{2x-4}$$

Dividing by 2x-4 undoes the multiplication by 2x-4.

$$y=\frac{3x-9}{2x-4}$$

Divide -9+3x by 2x-4.

$$y=\frac{3\left(x-3\right)}{2\left(x-2\right)}$$