Solve 2xy+3=4x

$$2xy+3=4x$$

Solve for x

$$x=-\frac{3}{2\left(y-2\right)}$$

$$y\neq 2$$

Steps for Solving Linear Equation

Subtract 4x from both sides.

$$2xy+3-4x=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$2xy-4x=-3$$

Combine all terms containing x.

$$\left(2y-4\right)x=-3$$

Divide both sides by 2y-4.

$$\frac{\left(2y-4\right)x}{2y-4}=-\frac{3}{2y-4}$$

Dividing by 2y-4 undoes the multiplication by 2y-4.

$$x=-\frac{3}{2y-4}$$

Divide -3 by 2y-4.

$$x=-\frac{3}{2\left(y-2\right)}$$

Solve for y

$$y=2-\frac{3}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 3 from both sides.

$$2xy=4x-3$$

Divide both sides by 2x.

$$\frac{2xy}{2x}=\frac{4x-3}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$y=\frac{4x-3}{2x}$$

Divide 4x-3 by 2x.

$$y=2-\frac{3}{2x}$$