Solve for x
x=-\frac{\theta +e}{2e}
Solve for θ
\theta =-e\left(2x+1\right)
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2xe+\theta =-e
Subtract e from both sides. Anything subtracted from zero gives its negation.
2xe=-e-\theta
Subtract \theta from both sides.
2ex=-\theta -e
The equation is in standard form.
\frac{2ex}{2e}=\frac{-\theta -e}{2e}
Divide both sides by 2e.
x=\frac{-\theta -e}{2e}
Dividing by 2e undoes the multiplication by 2e.
x=-\frac{\theta }{2e}-\frac{1}{2}
Divide -e-\theta by 2e.
e+\theta =-2xe
Subtract 2xe from both sides. Anything subtracted from zero gives its negation.
\theta =-2xe-e
Subtract e from both sides.
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