Solve 2x2x2x2x2x=11

$$2x2x2x2x2x=11$$

Solve for x

$$x=\frac{11}{2x_{2}^{4}}$$

$$x_{2}\neq 0$$

Steps for Solving Linear Equation

Multiply x_{2} and x_{2} to get x_{2}^{2}.

$$2x_{2}^{2}x_{2}x_{2}x=11$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$2x_{2}^{3}x_{2}x=11$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$2x_{2}^{4}x=11$$

Divide both sides by 2x_{2}^{4}.

$$\frac{2x_{2}^{4}x}{2x_{2}^{4}}=\frac{11}{2x_{2}^{4}}$$

Dividing by 2x_{2}^{4} undoes the multiplication by 2x_{2}^{4}.

$$x=\frac{11}{2x_{2}^{4}}$$

Solve for x_2 (complex solution)

$$x_{2}=\frac{2^{\frac{3}{4}}\sqrt[4]{11}ix^{-\frac{1}{4}}}{2}$$

$$x_{2}=\frac{2^{\frac{3}{4}}\sqrt[4]{11}x^{-\frac{1}{4}}}{2}$$

$$x_{2}=-\frac{2^{\frac{3}{4}}\sqrt[4]{11}x^{-\frac{1}{4}}}{2}$$

$$x_{2}=-\frac{2^{\frac{3}{4}}\sqrt[4]{11}ix^{-\frac{1}{4}}}{2}\text{, }x\neq 0$$

Solve for x_2

$$x_{2}=\frac{\sqrt[4]{\frac{88}{x}}}{2}$$

$$x_{2}=-\frac{\sqrt[4]{\frac{88}{x}}}{2}\text{, }x>0$$