Solve 2x1+12x2+22x3=4

$$2x1+12x2+22x3=4$$

Solve for x_1

$$x_{1}=2-11x_{3}-6x_{2}$$

Steps for Solving Linear Equation

Subtract 12x_{2} from both sides.

$$2x_{1}+22x_{3}=4-12x_{2}$$

Subtract 22x_{3} from both sides.

$$2x_{1}=4-12x_{2}-22x_{3}$$

The equation is in standard form.

$$2x_{1}=4-22x_{3}-12x_{2}$$

Divide both sides by 2.

$$\frac{2x_{1}}{2}=\frac{4-22x_{3}-12x_{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x_{1}=\frac{4-22x_{3}-12x_{2}}{2}$$

Divide 4-12x_{2}-22x_{3} by 2.

$$x_{1}=2-11x_{3}-6x_{2}$$

Solve for x_2

$$x_{2}=-\frac{x_{1}}{6}-\frac{11x_{3}}{6}+\frac{1}{3}$$

Steps for Solving Linear Equation

Subtract 2x_{1} from both sides.

$$12x_{2}+22x_{3}=4-2x_{1}$$

Subtract 22x_{3} from both sides.

$$12x_{2}=4-2x_{1}-22x_{3}$$

The equation is in standard form.

$$12x_{2}=4-22x_{3}-2x_{1}$$

Divide both sides by 12.

$$\frac{12x_{2}}{12}=\frac{4-22x_{3}-2x_{1}}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x_{2}=\frac{4-22x_{3}-2x_{1}}{12}$$

Divide 4-2x_{1}-22x_{3} by 12.

$$x_{2}=-\frac{x_{1}}{6}-\frac{11x_{3}}{6}+\frac{1}{3}$$