Solve for x
x=-\frac{\sqrt{3}y}{2}-y+3\sqrt{3}+3
Solve for y
y=2\left(\sqrt{3}x-2x+3\sqrt{3}-3\right)
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2x-y\sqrt{3}+12=x\times 2\sqrt{3}+y
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
2x-y\sqrt{3}+12-x\times 2\sqrt{3}=y
Subtract x\times 2\sqrt{3} from both sides.
2x-y\sqrt{3}+12-2x\sqrt{3}=y
Multiply -1 and 2 to get -2.
2x+12-2x\sqrt{3}=y+y\sqrt{3}
Add y\sqrt{3} to both sides.
2x-2x\sqrt{3}=y+y\sqrt{3}-12
Subtract 12 from both sides.
\left(2-2\sqrt{3}\right)x=y+y\sqrt{3}-12
Combine all terms containing x.
\left(2-2\sqrt{3}\right)x=\sqrt{3}y+y-12
The equation is in standard form.
\frac{\left(2-2\sqrt{3}\right)x}{2-2\sqrt{3}}=\frac{\sqrt{3}y+y-12}{2-2\sqrt{3}}
Divide both sides by 2-2\sqrt{3}.
x=\frac{\sqrt{3}y+y-12}{2-2\sqrt{3}}
Dividing by 2-2\sqrt{3} undoes the multiplication by 2-2\sqrt{3}.
x=-\frac{\sqrt{3}y}{2}-y+3\sqrt{3}+3
Divide y+y\sqrt{3}-12 by 2-2\sqrt{3}.
2x-y\sqrt{3}+12=x\times 2\sqrt{3}+y
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
2x-y\sqrt{3}+12-y=x\times 2\sqrt{3}
Subtract y from both sides.
2x-y\sqrt{3}-y=x\times 2\sqrt{3}-12
Subtract 12 from both sides.
-y\sqrt{3}-y=x\times 2\sqrt{3}-12-2x
Subtract 2x from both sides.
\left(-\sqrt{3}-1\right)y=x\times 2\sqrt{3}-12-2x
Combine all terms containing y.
\left(-\sqrt{3}-1\right)y=2\sqrt{3}x-2x-12
The equation is in standard form.
\frac{\left(-\sqrt{3}-1\right)y}{-\sqrt{3}-1}=\frac{2\sqrt{3}x-2x-12}{-\sqrt{3}-1}
Divide both sides by -\sqrt{3}-1.
y=\frac{2\sqrt{3}x-2x-12}{-\sqrt{3}-1}
Dividing by -\sqrt{3}-1 undoes the multiplication by -\sqrt{3}-1.
y=\left(1-\sqrt{3}\right)\left(\sqrt{3}x-x-6\right)
Divide 2\sqrt{3}x-12-2x by -\sqrt{3}-1.
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