Solve for x
x\geq \frac{92}{3}
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3x-92\geq 0
Combine 2x and x to get 3x.
3x\geq 92
Add 92 to both sides. Anything plus zero gives itself.
x\geq \frac{92}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
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