Solve 2x-527-x-6+3xy-28=39

$$2x-527-x-6+3xy-28 = 39$$

Solve for x

$$x=\frac{600}{3y+1}$$

$$y\neq -\frac{1}{3}$$

Steps for Solving Linear Equation

Combine 2x and -x to get x.

$$x-527-6+3xy-28=39$$

Subtract 6 from -527 to get -533.

$$x-533+3xy-28=39$$

Subtract 28 from -533 to get -561.

$$x-561+3xy=39$$

Add 561 to both sides.

$$x+3xy=39+561$$

Add 39 and 561 to get 600.

$$x+3xy=600$$

Combine all terms containing x.

$$\left(1+3y\right)x=600$$

The equation is in standard form.

$$\left(3y+1\right)x=600$$

Divide both sides by 1+3y.

$$\frac{\left(3y+1\right)x}{3y+1}=\frac{600}{3y+1}$$

Dividing by 1+3y undoes the multiplication by 1+3y.

$$x=\frac{600}{3y+1}$$

Solve for y

$$y=-\frac{1}{3}+\frac{200}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Combine 2x and -x to get x.

$$x-527-6+3xy-28=39$$

Subtract 6 from -527 to get -533.

$$x-533+3xy-28=39$$

Subtract 28 from -533 to get -561.

$$x-561+3xy=39$$

Subtract x from both sides.

$$-561+3xy=39-x$$

Add 561 to both sides.

$$3xy=39-x+561$$

Add 39 and 561 to get 600.

$$3xy=600-x$$

Divide both sides by 3x.

$$\frac{3xy}{3x}=\frac{600-x}{3x}$$

Dividing by 3x undoes the multiplication by 3x.

$$y=\frac{600-x}{3x}$$

Divide 600-x by 3x.

$$y=-\frac{1}{3}+\frac{200}{x}$$