Solve 2x-5+4-3x

$$2x-5+4-3x$$

Evaluate

$$-x-1$$

Solution Steps

Add -5 and 4 to get -1.

$$2x-1-3x$$

Combine 2x and -3x to get -x.

$$-x-1$$

Differentiate w.r.t. x

$$-1$$

Steps Using Derivative Rule for Sum

Add -5 and 4 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-1-3x)$$

Combine 2x and -3x to get -x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-x^{1-1}$$

Subtract 1 from 1.

$$-x^{0}$$

For any term t except 0, t^{0}=1.

$$-1$$