Solve 2x-5*(6-2x)-8+(x-1)=0

$$2x-5 \times (6-2x)-8+(x-1)=0$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Use the distributive property to multiply -5 by 6-2x.

$$2x-30+10x-8+x-1=0$$

Combine 2x and 10x to get 12x.

$$12x-30-8+x-1=0$$

Subtract 8 from -30 to get -38.

$$12x-38+x-1=0$$

Combine 12x and x to get 13x.

$$13x-38-1=0$$

Subtract 1 from -38 to get -39.

$$13x-39=0$$

Add 39 to both sides. Anything plus zero gives itself.

$$13x=39$$

Divide both sides by 13.

$$x=\frac{39}{13}$$

Divide 39 by 13 to get 3.

$$x=3$$