Solve 2x-4-4/x+1

$$2x-4- \frac{ 4 }{ x+1 }$$

Evaluate

$$\frac{2\left(x^{2}-x-4\right)}{x+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2x-4 times \frac{x+1}{x+1}.

$$\frac{\left(2x-4\right)\left(x+1\right)}{x+1}-\frac{4}{x+1}$$

Since \frac{\left(2x-4\right)\left(x+1\right)}{x+1} and \frac{4}{x+1} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(2x-4\right)\left(x+1\right)-4}{x+1}$$

Do the multiplications in \left(2x-4\right)\left(x+1\right)-4.

$$\frac{2x^{2}+2x-4x-4-4}{x+1}$$

Combine like terms in 2x^{2}+2x-4x-4-4.

$$\frac{2x^{2}-2x-8}{x+1}$$

Factor

$$\frac{2\left(x-\frac{1-\sqrt{17}}{2}\right)\left(x-\frac{\sqrt{17}+1}{2}\right)}{x+1}$$