Solve 2x-42^2-3

$$2x-4 { 2 }^{ 2 } -3$$

Evaluate

$$2x-19$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$2x-4\times 4-3$$

Multiply 4 and 4 to get 16.

$$2x-16-3$$

Subtract 3 from -16 to get -19.

$$2x-19$$

Differentiate w.r.t. x

$$2$$

Steps Using Derivative Rule for Sum

Calculate 2 to the power of 2 and get 4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-4\times 4-3)$$

Multiply 4 and 4 to get 16.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-16-3)$$

Subtract 3 from -16 to get -19.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-19)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2x^{1-1}$$

Subtract 1 from 1.

$$2x^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$