Solve 2x-4left(2x-3right)=6-2left(x+1right)

$$2x-4 \left( 2x-3 \right) = 6-2 \left( x+1 \right)$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use the distributive property to multiply -4 by 2x-3.

$$2x-8x+12=6-2\left(x+1\right)$$

Combine 2x and -8x to get -6x.

$$-6x+12=6-2\left(x+1\right)$$

Use the distributive property to multiply -2 by x+1.

$$-6x+12=6-2x-2$$

Subtract 2 from 6 to get 4.

$$-6x+12=4-2x$$

Add 2x to both sides.

$$-6x+12+2x=4$$

Combine -6x and 2x to get -4x.

$$-4x+12=4$$

Subtract 12 from both sides.

$$-4x=4-12$$

Subtract 12 from 4 to get -8.

$$-4x=-8$$

Divide both sides by -4.

$$x=\frac{-8}{-4}$$

Divide -8 by -4 to get 2.

$$x=2$$