Solve for x
x=\frac{3z+17}{2}
Solve for z
z=\frac{2x-17}{3}
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2x=17+3z
Add 3z to both sides.
2x=3z+17
The equation is in standard form.
\frac{2x}{2}=\frac{3z+17}{2}
Divide both sides by 2.
x=\frac{3z+17}{2}
Dividing by 2 undoes the multiplication by 2.
-3z=17-2x
Subtract 2x from both sides.
\frac{-3z}{-3}=\frac{17-2x}{-3}
Divide both sides by -3.
z=\frac{17-2x}{-3}
Dividing by -3 undoes the multiplication by -3.
z=\frac{2x-17}{3}
Divide 17-2x by -3.
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