Solve for x
x=\frac{3y}{2}+2z+2
Solve for y
y=\frac{2\left(x-2z-2\right)}{3}
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2x-4z=4+3y
Add 3y to both sides.
2x=4+3y+4z
Add 4z to both sides.
2x=3y+4z+4
The equation is in standard form.
\frac{2x}{2}=\frac{3y+4z+4}{2}
Divide both sides by 2.
x=\frac{3y+4z+4}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{3y}{2}+2z+2
Divide 4+3y+4z by 2.
-3y-4z=4-2x
Subtract 2x from both sides.
-3y=4-2x+4z
Add 4z to both sides.
-3y=4+4z-2x
The equation is in standard form.
\frac{-3y}{-3}=\frac{4+4z-2x}{-3}
Divide both sides by -3.
y=\frac{4+4z-2x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{2x-4z-4}{3}
Divide 4-2x+4z by -3.
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Limits
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