Solve for x
x=\frac{3y}{2}+8
Solve for y
y=\frac{2\left(x-8\right)}{3}
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2x=3y+16
The equation is in standard form.
\frac{2x}{2}=\frac{3y+16}{2}
Divide both sides by 2.
x=\frac{3y+16}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{3y}{2}+8
Divide 3y+16 by 2.
3y+16=2x
Swap sides so that all variable terms are on the left hand side.
3y=2x-16
Subtract 16 from both sides.
\frac{3y}{3}=\frac{2x-16}{3}
Divide both sides by 3.
y=\frac{2x-16}{3}
Dividing by 3 undoes the multiplication by 3.
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