Solve for x
x=-\frac{z}{3}+60
Solve for z
z=180-3x
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3x+z=180
Combine 2x and x to get 3x.
3x=180-z
Subtract z from both sides.
\frac{3x}{3}=\frac{180-z}{3}
Divide both sides by 3.
x=\frac{180-z}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{z}{3}+60
Divide 180-z by 3.
3x+z=180
Combine 2x and x to get 3x.
z=180-3x
Subtract 3x from both sides.
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