Solve for y
y=2+3z-2x
Solve for x
x=\frac{3z}{2}-\frac{y}{2}+1
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2x+y-3z=1\times 2
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 2 is 2.
2x+y-3z=2
Multiply 1 and 2 to get 2.
y-3z=2-2x
Subtract 2x from both sides.
y=2-2x+3z
Add 3z to both sides.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}