Solve for x
x=\frac{3-z-y}{2}
Solve for y
y=3-z-2x
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2x+z=3-y
Subtract y from both sides.
2x=3-y-z
Subtract z from both sides.
2x=3-z-y
The equation is in standard form.
\frac{2x}{2}=\frac{3-z-y}{2}
Divide both sides by 2.
x=\frac{3-z-y}{2}
Dividing by 2 undoes the multiplication by 2.
y+z=3-2x
Subtract 2x from both sides.
y=3-2x-z
Subtract z from both sides.
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