Solve 2x+x3x+9=8-6x

$$2x+x3x+9 = 8-6x$$

Solve for x

$$x=-\frac{1}{x_{3}+8}$$

$$x_{3}\neq -8$$

Steps for Solving Linear Equation

Add 6x to both sides.

$$2x+x_{3}x+9+6x=8$$

Combine 2x and 6x to get 8x.

$$8x+x_{3}x+9=8$$

Subtract 9 from both sides.

$$8x+x_{3}x=8-9$$

Subtract 9 from 8 to get -1.

$$8x+x_{3}x=-1$$

Combine all terms containing x.

$$\left(8+x_{3}\right)x=-1$$

The equation is in standard form.

$$\left(x_{3}+8\right)x=-1$$

Divide both sides by x_{3}+8.

$$\frac{\left(x_{3}+8\right)x}{x_{3}+8}=-\frac{1}{x_{3}+8}$$

Dividing by x_{3}+8 undoes the multiplication by x_{3}+8.

$$x=-\frac{1}{x_{3}+8}$$

Solve for x_3

$$x_{3}=-8-\frac{1}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$x_{3}x+9=8-6x-2x$$

Combine -6x and -2x to get -8x.

$$x_{3}x+9=8-8x$$

Subtract 9 from both sides.

$$x_{3}x=8-8x-9$$

Subtract 9 from 8 to get -1.

$$x_{3}x=-1-8x$$

The equation is in standard form.

$$xx_{3}=-8x-1$$

Divide both sides by x.

$$\frac{xx_{3}}{x}=\frac{-8x-1}{x}$$

Dividing by x undoes the multiplication by x.

$$x_{3}=\frac{-8x-1}{x}$$

Divide -1-8x by x.

$$x_{3}=-8-\frac{1}{x}$$