Solve for x
x=\frac{7z}{2}-\frac{5y}{2}+8
Solve for y
y=\frac{16+7z-2x}{5}
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2x-7z=16-5y
Subtract 5y from both sides.
2x=16-5y+7z
Add 7z to both sides.
2x=16+7z-5y
The equation is in standard form.
\frac{2x}{2}=\frac{16+7z-5y}{2}
Divide both sides by 2.
x=\frac{16+7z-5y}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{7z}{2}-\frac{5y}{2}+8
Divide 16-5y+7z by 2.
5y-7z=16-2x
Subtract 2x from both sides.
5y=16-2x+7z
Add 7z to both sides.
5y=16+7z-2x
The equation is in standard form.
\frac{5y}{5}=\frac{16+7z-2x}{5}
Divide both sides by 5.
y=\frac{16+7z-2x}{5}
Dividing by 5 undoes the multiplication by 5.
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Limits
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