Solve 2x+5y+15z-24.05=0

$$2x+5y+15z-24.05 = 0$$

Solve for x

$$x=-\frac{5y}{2}-\frac{15z}{2}+12.025$$

Steps for Solving Linear Equation

Subtract 5y from both sides. Anything subtracted from zero gives its negation.

$$2x+15z-24.05=-5y$$

Subtract 15z from both sides.

$$2x-24.05=-5y-15z$$

Add 24.05 to both sides.

$$2x=-5y-15z+24.05$$

The equation is in standard form.

$$2x=24.05-15z-5y$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{24.05-15z-5y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{24.05-15z-5y}{2}$$

Divide -5y-15z+24.05 by 2.

$$x=-\frac{5y}{2}-\frac{15z}{2}+\frac{481}{40}$$

Solve for y

$$y=-\frac{2x}{5}-3z+4.81$$

Steps for Solving Linear Equation

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$5y+15z-24.05=-2x$$

Subtract 15z from both sides.

$$5y-24.05=-2x-15z$$

Add 24.05 to both sides.

$$5y=-2x-15z+24.05$$

The equation is in standard form.

$$5y=24.05-15z-2x$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{24.05-15z-2x}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{24.05-15z-2x}{5}$$

Divide -2x-15z+24.05 by 5.

$$y=-\frac{2x}{5}-3z+\frac{481}{100}$$