Solve for x
x=-\frac{3y}{2}-6
Solve for y
y=-\frac{2x}{3}-4
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2x=-12-3y
Subtract 3y from both sides.
2x=-3y-12
The equation is in standard form.
\frac{2x}{2}=\frac{-3y-12}{2}
Divide both sides by 2.
x=\frac{-3y-12}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}-6
Divide -12-3y by 2.
3y=-12-2x
Subtract 2x from both sides.
3y=-2x-12
The equation is in standard form.
\frac{3y}{3}=\frac{-2x-12}{3}
Divide both sides by 3.
y=\frac{-2x-12}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2x}{3}-4
Divide -12-2x by 3.
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