Solve for x
x=-\frac{3y}{2}-2z+\frac{9}{2}
Solve for y
y=-\frac{2x}{3}-\frac{4z}{3}+3
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2x+4z=9-3y
Subtract 3y from both sides.
2x=9-3y-4z
Subtract 4z from both sides.
2x=9-4z-3y
The equation is in standard form.
\frac{2x}{2}=\frac{9-4z-3y}{2}
Divide both sides by 2.
x=\frac{9-4z-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}-2z+\frac{9}{2}
Divide 9-3y-4z by 2.
3y+4z=9-2x
Subtract 2x from both sides.
3y=9-2x-4z
Subtract 4z from both sides.
3y=9-4z-2x
The equation is in standard form.
\frac{3y}{3}=\frac{9-4z-2x}{3}
Divide both sides by 3.
y=\frac{9-4z-2x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2x}{3}-\frac{4z}{3}+3
Divide 9-2x-4z by 3.
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