Solve 2x+3y*3z=2

$$2x+3y \times 3z=2$$

Solve for x

$$x=-\frac{9yz}{2}+1$$

Steps for Solving Linear Equation

Multiply 3 and 3 to get 9.

$$2x+9yz=2$$

Subtract 9yz from both sides.

$$2x=2-9yz$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{2-9yz}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{2-9yz}{2}$$

Divide 2-9yz by 2.

$$x=-\frac{9yz}{2}+1$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{2\left(x-1\right)}{9z}\text{, }&z\neq 0\\y\in \mathrm{R}\text{, }&x=1\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 3 and 3 to get 9.

$$2x+9yz=2$$

Subtract 2x from both sides.

$$9yz=2-2x$$

The equation is in standard form.

$$9zy=2-2x$$

Divide both sides by 9z.

$$\frac{9zy}{9z}=\frac{2-2x}{9z}$$

Dividing by 9z undoes the multiplication by 9z.

$$y=\frac{2-2x}{9z}$$

Divide 2-2x by 9z.

$$y=\frac{2\left(1-x\right)}{9z}$$