Solve for x
x=-\frac{25y}{2}-3z+\frac{3}{2}
Solve for y
y=\frac{3-6z-2x}{25}
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2x+6z=3-25y
Subtract 25y from both sides.
2x=3-25y-6z
Subtract 6z from both sides.
2x=3-6z-25y
The equation is in standard form.
\frac{2x}{2}=\frac{3-6z-25y}{2}
Divide both sides by 2.
x=\frac{3-6z-25y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{25y}{2}-3z+\frac{3}{2}
Divide 3-25y-6z by 2.
25y+6z=3-2x
Subtract 2x from both sides.
25y=3-2x-6z
Subtract 6z from both sides.
25y=3-6z-2x
The equation is in standard form.
\frac{25y}{25}=\frac{3-6z-2x}{25}
Divide both sides by 25.
y=\frac{3-6z-2x}{25}
Dividing by 25 undoes the multiplication by 25.
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