Solve 2x+sqrt{8}=31

$$2x+ \sqrt{ 8 } =31$$

Solve for x

$$x=\frac{31}{2}-\sqrt{2}\approx 14.085786438$$

Steps for Solving Linear Equation

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$2x+2\sqrt{2}=31$$

Subtract 2\sqrt{2} from both sides.

$$2x=31-2\sqrt{2}$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{31-2\sqrt{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{31-2\sqrt{2}}{2}$$

Divide 31-2\sqrt{2} by 2.

$$x=\frac{31}{2}-\sqrt{2}$$