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xy^{4}\left(2y+3\right)-y^{4}\left(2y+3\right)+4\left(2y+3\right)
Do the grouping 2xy^{5}+3xy^{4}-2y^{5}-3y^{4}+8y+12=\left(2xy^{5}+3xy^{4}\right)+\left(-2y^{5}-3y^{4}\right)+\left(8y+12\right), and factor out xy^{4},-y^{4},4 in each of the groups respectively.
\left(2y+3\right)\left(xy^{4}-y^{4}+4\right)
Factor out common term 2y+3 by using distributive property.