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2x^{2}\times 7=2
Multiply x and x to get x^{2}.
14x^{2}=2
Multiply 2 and 7 to get 14.
x^{2}=\frac{2}{14}
Divide both sides by 14.
x^{2}=\frac{1}{7}
Reduce the fraction \frac{2}{14} to lowest terms by extracting and canceling out 2.
x=\frac{\sqrt{7}}{7} x=-\frac{\sqrt{7}}{7}
Take the square root of both sides of the equation.
2x^{2}\times 7=2
Multiply x and x to get x^{2}.
14x^{2}=2
Multiply 2 and 7 to get 14.
14x^{2}-2=0
Subtract 2 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 14\left(-2\right)}}{2\times 14}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 14 for a, 0 for b, and -2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 14\left(-2\right)}}{2\times 14}
Square 0.
x=\frac{0±\sqrt{-56\left(-2\right)}}{2\times 14}
Multiply -4 times 14.
x=\frac{0±\sqrt{112}}{2\times 14}
Multiply -56 times -2.
x=\frac{0±4\sqrt{7}}{2\times 14}
Take the square root of 112.
x=\frac{0±4\sqrt{7}}{28}
Multiply 2 times 14.
x=\frac{\sqrt{7}}{7}
Now solve the equation x=\frac{0±4\sqrt{7}}{28} when ± is plus.
x=-\frac{\sqrt{7}}{7}
Now solve the equation x=\frac{0±4\sqrt{7}}{28} when ± is minus.
x=\frac{\sqrt{7}}{7} x=-\frac{\sqrt{7}}{7}
The equation is now solved.