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2x^{2}\times 4=20
Multiply x and x to get x^{2}.
8x^{2}=20
Multiply 2 and 4 to get 8.
x^{2}=\frac{20}{8}
Divide both sides by 8.
x^{2}=\frac{5}{2}
Reduce the fraction \frac{20}{8} to lowest terms by extracting and canceling out 4.
x=\frac{\sqrt{10}}{2} x=-\frac{\sqrt{10}}{2}
Take the square root of both sides of the equation.
2x^{2}\times 4=20
Multiply x and x to get x^{2}.
8x^{2}=20
Multiply 2 and 4 to get 8.
8x^{2}-20=0
Subtract 20 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 8\left(-20\right)}}{2\times 8}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 8 for a, 0 for b, and -20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 8\left(-20\right)}}{2\times 8}
Square 0.
x=\frac{0±\sqrt{-32\left(-20\right)}}{2\times 8}
Multiply -4 times 8.
x=\frac{0±\sqrt{640}}{2\times 8}
Multiply -32 times -20.
x=\frac{0±8\sqrt{10}}{2\times 8}
Take the square root of 640.
x=\frac{0±8\sqrt{10}}{16}
Multiply 2 times 8.
x=\frac{\sqrt{10}}{2}
Now solve the equation x=\frac{0±8\sqrt{10}}{16} when ± is plus.
x=-\frac{\sqrt{10}}{2}
Now solve the equation x=\frac{0±8\sqrt{10}}{16} when ± is minus.
x=\frac{\sqrt{10}}{2} x=-\frac{\sqrt{10}}{2}
The equation is now solved.