Solve 2x*ln(x)+x^2/x

$$2x \times \ln ( x ) + \frac{ { x }^{ 2 } }{ x }$$

Factor

$$x\left(2\ln(x)+1\right)$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$factor(2x\log_{e}\left(x\right)+x^{1})$$

Calculate x to the power of 1 and get x.

$$factor(2x\log_{e}\left(x\right)+x)$$

Factor out x.

$$x\left(2\log_{e}\left(x\right)+1\right)$$

Evaluate

$$2x\ln(x)+x$$