Solve for f
f=1-\frac{1}{2x}
x\neq 0
Solve for x
x=-\frac{1}{2\left(f-1\right)}
f\neq 1
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2xf=2x-1
The equation is in standard form.
\frac{2xf}{2x}=\frac{2x-1}{2x}
Divide both sides by 2x.
f=\frac{2x-1}{2x}
Dividing by 2x undoes the multiplication by 2x.
f=1-\frac{1}{2x}
Divide 2x-1 by 2x.
2fx-2x=-1
Subtract 2x from both sides.
\left(2f-2\right)x=-1
Combine all terms containing x.
\frac{\left(2f-2\right)x}{2f-2}=-\frac{1}{2f-2}
Divide both sides by 2f-2.
x=-\frac{1}{2f-2}
Dividing by 2f-2 undoes the multiplication by 2f-2.
x=-\frac{1}{2\left(f-1\right)}
Divide -1 by 2f-2.
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