Solve for b
b=\frac{d-8}{2}
Solve for d
d=2\left(b+4\right)
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2b=-8+d
Add d to both sides.
2b=d-8
The equation is in standard form.
\frac{2b}{2}=\frac{d-8}{2}
Divide both sides by 2.
b=\frac{d-8}{2}
Dividing by 2 undoes the multiplication by 2.
b=\frac{d}{2}-4
Divide -8+d by 2.
-d=-8-2b
Subtract 2b from both sides.
-d=-2b-8
The equation is in standard form.
\frac{-d}{-1}=\frac{-2b-8}{-1}
Divide both sides by -1.
d=\frac{-2b-8}{-1}
Dividing by -1 undoes the multiplication by -1.
d=2b+8
Divide -8-2b by -1.
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