Solve 294x^4-96x^2y^2

$$294 x ^ { 4 } - 96 x ^ { 2 } y ^ { 2 }$$

Factor

$$6\left(7x-4y\right)\left(7x+4y\right)x^{2}$$

Solution Steps

Factor out 6.

$$6\left(49x^{4}-16x^{2}y^{2}\right)$$

Consider 49x^{4}-16x^{2}y^{2}. Factor out x^{2}.

$$x^{2}\left(49x^{2}-16y^{2}\right)$$

Consider 49x^{2}-16y^{2}. Rewrite 49x^{2}-16y^{2} as \left(7x\right)^{2}-\left(4y\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(7x-4y\right)\left(7x+4y\right)$$

Rewrite the complete factored expression.

$$6x^{2}\left(7x-4y\right)\left(7x+4y\right)$$

Evaluate

$$294x^{4}-96\left(xy\right)^{2}$$