Solve 2921/2*11/13+(-27/8)

$$292 \frac { 1 } { 2 } \times \frac { 11 } { 13 } + ( - 2 \frac { 7 } { 8 } )$$

Evaluate

$$\frac{1957}{8}=244.625$$

Solution Steps

Multiply 292 and 2 to get 584.

$$\frac{584+1}{2}\times \frac{11}{13}-\frac{2\times 8+7}{8}$$

Add 584 and 1 to get 585.

$$\frac{585}{2}\times \frac{11}{13}-\frac{2\times 8+7}{8}$$

Multiply \frac{585}{2} times \frac{11}{13} by multiplying numerator times numerator and denominator times denominator.

$$\frac{585\times 11}{2\times 13}-\frac{2\times 8+7}{8}$$

Do the multiplications in the fraction \frac{585\times 11}{2\times 13}.

$$\frac{6435}{26}-\frac{2\times 8+7}{8}$$

Reduce the fraction \frac{6435}{26} to lowest terms by extracting and canceling out 13.

$$\frac{495}{2}-\frac{2\times 8+7}{8}$$

Multiply 2 and 8 to get 16.

$$\frac{495}{2}-\frac{16+7}{8}$$

Add 16 and 7 to get 23.

$$\frac{495}{2}-\frac{23}{8}$$

Least common multiple of 2 and 8 is 8. Convert \frac{495}{2} and \frac{23}{8} to fractions with denominator 8.

$$\frac{1980}{8}-\frac{23}{8}$$

Since \frac{1980}{8} and \frac{23}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1980-23}{8}$$

Subtract 23 from 1980 to get 1957.

$$\frac{1957}{8}$$

Factor

$$\frac{19 \cdot 103}{2 ^ {3}} = 244\frac{5}{8} = 244.625$$