Solve 292=Ae^2kquad637=Ae^28u

$$292 = A e ^ { 2 k } \quad 637 = A e ^ { 28 u }$$

Evaluate (complex solution)

$$292=637Ae^{2k}\text{ and }637Ae^{2k}=Ae^{28u}$$

Solve for u

$$u=\frac{2k+\ln(637)}{28}$$

$$A=\frac{292}{637e^{2k}}$$

Solve for k

$$k=14u-\frac{\ln(13)}{2}-\ln(7)$$

$$A=\frac{292}{e^{28u}}$$