Solve for x
x = \frac{11}{10} = 1\frac{1}{10} = 1.1
x = -\frac{11}{10} = -1\frac{1}{10} = -1.1
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x^{2}=\frac{3509}{2900}
Divide both sides by 2900.
x^{2}=\frac{121}{100}
Reduce the fraction \frac{3509}{2900} to lowest terms by extracting and canceling out 29.
x^{2}-\frac{121}{100}=0
Subtract \frac{121}{100} from both sides.
100x^{2}-121=0
Multiply both sides by 100.
\left(10x-11\right)\left(10x+11\right)=0
Consider 100x^{2}-121. Rewrite 100x^{2}-121 as \left(10x\right)^{2}-11^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{11}{10} x=-\frac{11}{10}
To find equation solutions, solve 10x-11=0 and 10x+11=0.
x^{2}=\frac{3509}{2900}
Divide both sides by 2900.
x^{2}=\frac{121}{100}
Reduce the fraction \frac{3509}{2900} to lowest terms by extracting and canceling out 29.
x=\frac{11}{10} x=-\frac{11}{10}
Take the square root of both sides of the equation.
x^{2}=\frac{3509}{2900}
Divide both sides by 2900.
x^{2}=\frac{121}{100}
Reduce the fraction \frac{3509}{2900} to lowest terms by extracting and canceling out 29.
x^{2}-\frac{121}{100}=0
Subtract \frac{121}{100} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{121}{100}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{121}{100} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{121}{100}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{121}{25}}}{2}
Multiply -4 times -\frac{121}{100}.
x=\frac{0±\frac{11}{5}}{2}
Take the square root of \frac{121}{25}.
x=\frac{11}{10}
Now solve the equation x=\frac{0±\frac{11}{5}}{2} when ± is plus.
x=-\frac{11}{10}
Now solve the equation x=\frac{0±\frac{11}{5}}{2} when ± is minus.
x=\frac{11}{10} x=-\frac{11}{10}
The equation is now solved.
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