Solve for x
x=-\frac{y}{2}-\frac{z}{3}+\frac{29}{6}
Solve for y
y=-\frac{2z}{3}-2x+\frac{29}{3}
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6x+3y+2z=29
Swap sides so that all variable terms are on the left hand side.
6x+2z=29-3y
Subtract 3y from both sides.
6x=29-3y-2z
Subtract 2z from both sides.
6x=29-2z-3y
The equation is in standard form.
\frac{6x}{6}=\frac{29-2z-3y}{6}
Divide both sides by 6.
x=\frac{29-2z-3y}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{y}{2}-\frac{z}{3}+\frac{29}{6}
Divide 29-3y-2z by 6.
6x+3y+2z=29
Swap sides so that all variable terms are on the left hand side.
3y+2z=29-6x
Subtract 6x from both sides.
3y=29-6x-2z
Subtract 2z from both sides.
3y=29-2z-6x
The equation is in standard form.
\frac{3y}{3}=\frac{29-2z-6x}{3}
Divide both sides by 3.
y=\frac{29-2z-6x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2z}{3}-2x+\frac{29}{3}
Divide 29-6x-2z by 3.
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