Solve 28a^3b^4:(-7ab^3)

$$28 a ^ { 3 } b ^ { 4 } : ( - 7 a b ^ { 3 } )$$

Evaluate

$$-4ba^{2}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{28^{1}a^{3}b^{4}}{\left(-7\right)^{1}a^{1}b^{3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{28^{1}}{\left(-7\right)^{1}}a^{3-1}b^{4-3}$$

Subtract 1 from 3.

$$\frac{28^{1}}{\left(-7\right)^{1}}a^{2}b^{4-3}$$

Subtract 3 from 4.

$$\frac{28^{1}}{\left(-7\right)^{1}}a^{2}b^{1}$$

Divide 28 by -7.

$$-4a^{2}b$$

Differentiate w.r.t. b

$$-4a^{2}$$